6v^2-11v=95

Solution for 6v^2-11v=95 equation:

6v^2-11v=95

We move all terms to the left:

6v^2-11v-(95)=0

a = 6; b = -11; c = -95;
Δ = b2-4ac
Δ = -112-4·6·(-95)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-49}{2*6}=\frac{-38}{12}
=-3+1/6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+49}{2*6}=\frac{60}{12}
=5
$